Home » , » Problem and Solution : Thermal expansion part-2

Problem and Solution : Thermal expansion part-2

Written By onfisika on Wednesday, April 2, 2014 | 6:43 PM

Problem

Estimate the percentage change in the density of the iron when it is still solid, but deep within the earth where temperatures of 2,000 degrees Celsius and a pressure of 5000 atm. Think of the bulk modulus and volume expansion coefficient does not vary with temperature and at normal room temperature. Bulk modulus for steel is around 90. 10 ^ 9 N / m square.

 

Solution

We consider a fixed mass of iron . The change in volume from the temperature change is

image

The change in volume from the pressure change depends on the bulk modulus :

image 

Because the density is mass/volume , for the fractional change in the density we have

image

 

Problem

An ordinary glass is filled to the brim with 350 ml of water at 100 degrees Celsius. If the temperature drops to 20 degrees Celsius, how much water can be added to the glass?

Solution

The contraction of the glass causes the enclosed volume to decrease as if it were glass. The volume of water that can be added is

image

 

Problem

Seen that 65.5 mL of water at 20 degrees Celsius meet sebuh vessel to the brim. When the vessel and the water is heated to 60 degrees Celsius, 0.35 grams of water lost. (A) how the coefficient of volume expansion vessel? (What is most likely matter to the vessel? Density of water at 60 degrees Celsius 0.98324 g / mL

Solution

 

(a) The expansion of the container causes the enclosed volume to increase as if it were made of the same material as the container . The volume of water that was lost is

image

 

(b) Aluminium is the most likely material

Comments
0 Comments

0 komentar :

Post a Comment