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The Equation of Continuity

Written By onfisika on Monday, March 18, 2013 | 7:01 AM

You may have noticed that you can increase the speed of the water emerging from a garden hose by partially closing the hose opening with your thumb. Apparently the speed v of the water depends on the cross – sectional area A through which the water flows.

Here we wish to derive an expression that relates v and A for the steady flow of an ideal fluid through a tube with varying cross section, like that in figure

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The flow there is toward the right, and the tube segment shown ( part of a longer tube ) has length L. The fluid has speeds v1 at the left end of the segment and v2 at the right end. The tube has cross – sectional areas A1 at the left end A2 at the right end. Suppose that in a time interval t a volume V of fluid enters the tube segments at its left end. Then, because the fluid is incompressible , an indentical volume V must emerge from the right end of the segment .

We can use this common volume V to relate the speeds and areas . To do so, we first consider figure

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Which shows a side view of a tube of uniform cross-sectional area A. In Figure a, a fluid element e is about to pass through the dashed line drawn across the tube width. The element’s speed is v , so during a time interval t , the element moves along the tube a distance x = v t . The volume V of fluid that has passed through the dassed line in that time interval t is

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Applying to both the left and right ends of the tube segments , we have

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This relation between speed and cross-sectional area is called the equation of continuity for the flow of an ideal fluid. It tells us that the flow speed increases when we decrease the cross-sectional area through which the fluid flows.

Equation A1v1 = A2v2 applies not only to an actual tube but also to any so-called tube of flow, or imaginary tube whose boundary consists of streamlines. Such a tube acts like a real tube because no fluid element can cross a streamline; thus, all the fluid within a tube of flow must remain within its boundary. Figure

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Shows a tube of flow in which the cross- sectional area increases from A1 to area A2 along the flow direction. From equation A1v1 = A2v2 we know that, with the increase in area , the speed must decrease, as is indicated by the greater spacing between streamlines at the right in figure. Similarly, you can see that figure

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The speed of the flow is greatest just above and just below the cylinder.

We can rewrite equation A1v1 = A2v as

Rv = Av = a constant

In which Rv is the volume flow rate of the fluid ( volume past given point per unit time ). Its SI unit is the cubic meter per second ( m3 /s ) . If the density rho of the fluid is uniform, we can multiply equation Rv = Av by that density to get the mass flow rate Rm ( mass per unit time ):

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The SI unit of mass flow rate is the kilogram per second. The equation says that the mass that flow into tube segement of figure

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each second must be equal to the mass that flows out of that segment each second.

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